Citicorp question papers with Answers for Citicorp Information Technology Industries Limited recruitment exam 2006 is here. Check the following written recruitment papers or placement papers of Citicorp.
CITICORP placement paper 1
Company : Citicorp
C questions
main()
{
int x=10,y=15;
x=x++;
y=++y;
printf(“%d %d\n”,x,y);
}
int x;
main()
{
int x=0;
{
int x=10;
x++;
change_value(x);
x++;
Modify_value();
printf(“First output: %d\n”,x);
}
x++;
change_value(x);
printf(“Second Output : %d\n”,x);
Modify_value();
printf(“Third Output : %d\n”,x);
}
Modify_value()
{
return (x+=10);
}
change_value()
{
return(x+=1);
}
main()
{
int x=20,y=35;
x = y++ + x++;
y = ++y + ++x;
printf(“%d %d\n”,x,y);
}
main()
{
char *p1=”Name”;
char *p2;
p2=(char *)malloc(20);
while(*p2++=*p1++);
printf(“%s\n”,p2);
}
main()
{
int x=5;
printf(“%d %d %d\n”,x,x<<2,x>>2);
}
#define swap1(a,b) a=a+b;b=a-b;a=a-b;
main()
{
int x=5,y=10;
swap1(x,y);
printf(“%d %d\n”,x,y);
swap2(x,y);
printf(“%d %d\n”,x,y);
}
int swap2(int a,int b)
{
int temp;
temp=a;
b=a;
a=temp;
return;
}
main()
{
char *ptr = “Ramco Systems”;
(*ptr)++;
printf(“%s\n”,ptr);
ptr++;
printf(“%s\n”,ptr);
}
#include
main()
{
char s1[]=”Ramco”;
char s2[]=”Systems”;
s1=s2;
printf(“%s”,s1);
}
#include
main()
{
char *p1;
char *p2;
p1=(char *) malloc(25);
p2=(char *) malloc(25);
strcpy(p1,”Ramco”);
strcpy(p2,”Systems”);
strcat(p1,p2);
printf(“%s”,p1);
}
1.enum day = { jan = 1 ,feb=4, april, may}
what is the value of may?
a)4 b)5 c)6 d)11
e)none of the above
2.main
{
int x,j,k;
j=k=6;x=2; ans x=1
x=j*k;
printf(“%d”, x);
3. fn f(x)
{ if(x<=0)
return; ans fn(5) ….?
else f(x-1)+x;
? Help M Main Menu P PrevMsg
return; ans fn(5) ….?
else f(x-1)+x;
}
4. i=20,k=0;
for(j=1;j
{
k+=j<10?4:3;
}
printf(“%d”, k); ans k=4
5. int i =10
main()
{
int i =20,n;
for(n=0;n<=i;)
{
int i=10
i++;
? Help M Main Menu P PrevMint i=10
i++;
}
printf(“%d”, i); ans i=20
6. int x=5;
y= x&y
( MULTIPLE CHOICE QS)
ans : c
7. Y=10;
if( Y++>9 && Y++!=10 && Y++>10)
printf(“…….. Y);
else printf(“”…. )
ans : 13
8. f=(x>y)?x:y
a) f points to max of x and y8. f=(x>y)?x:y
a) f points to max of x and y
b) f points to min of x and y
c)error
d) ……..
ans : a
9. if x is even, then
(x%2)=0
x &1 !=1
x! ( some stuff is there)
a)only two are correct
b) three are correct
c), d) ….
c), d) ….
ans : all are correct
10. which of the function operator cannot be over loaded
a) <= b)?: c)== d)*
ans: b and d
SECTION.C (PRG SKILLS)
(1) STRUCT DOUBLELIST
{ DOUBLE CLINKED
INT DET; LIST VOID
